Oxygen uptake in zebrafish eggs 24 hours after fetilization
Step 1: Find the Δ [O2] in nmol/ml
1 μmol/L = 1 nmol/mL
Δ [O2]= Start[O2)-End[O2]
Δ [O2] = 242.61 nmol/mL - 196.48 nmol/mL
Δ [O2]=46.13 nmol/mL
Step 2: Define Δ t in hours.
The Δ t is already defined in the table as 3 hours and 58 minutes.
Δ t (hours) = (Duration in hours) + (x minutes/60 minutes h-1)
Δ t (hours) = 3 hours + (58min/60 minutes h-1)
Δ t (hours) = 3.96 h
Step 3: Oxygen uptake (nmol/ind/h)
= [(Δ [O2] in nmol/mL) x (Volume (mL)] / [(# ind.) x (Δ t (hours)]
= (46.13 nmol/L x 5 ml) / (10 individuals x 3.96 h)
= 5.82 nmol/ind/h
Note that the calculations are simplified. The volume used here is the volume of water in the vial. This is because we expect that the total volume of the fish eggs are so small compared to change the volume of water in the vial.